Linear Algebra Examples

p (2) = - x^{3} - x^{2} + 5 x + 5

$p (2) = - x^{3} - x^{2} + 5 x + 5$

Step 1

Divide each term in

p (2) = - x^{3} - x^{2} + 5 x + 5

$p (2) = - x^{3} - x^{2} + 5 x + 5$ by

2

$2$ .

\frac{p \cdot 2}{2} = \frac{- x^{3}}{2} + \frac{- x^{2}}{2} + \frac{5 x}{2} + \frac{5}{2}

$\frac{p \cdot 2}{2} = \frac{- x^{3}}{2} + \frac{- x^{2}}{2} + \frac{5 x}{2} + \frac{5}{2}$

Step 2

Simplify the left side.

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Step 2.1

Cancel the common factor of

2

$2$ .

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Step 2.1.1

Cancel the common factor.

$\frac{p \cdot 2}{2} = \frac{- x^{3}}{2} + \frac{- x^{2}}{2} + \frac{5 x}{2} + \frac{5}{2}$

Step 2.1.2

Divide

$p$ by

$1$ .

$p = \frac{- x^{3}}{2} + \frac{- x^{2}}{2} + \frac{5 x}{2} + \frac{5}{2}$

Step 3

Simplify the right side.

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Step 3.1

Simplify each term.

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Step 3.1.1

Move the negative in front of the fraction.

$p = - \frac{x^{3}}{2} + \frac{- x^{2}}{2} + \frac{5 x}{2} + \frac{5}{2}$

Step 3.1.2

Move the negative in front of the fraction.

$p = - \frac{x^{3}}{2} - \frac{x^{2}}{2} + \frac{5 x}{2} + \frac{5}{2}$